Class DatabaseStorage can be used with either FileField or ImageField. It can be used to map filenames to database blobs: so you have to use it with a special additional table created manually. The table should contain a pk-column for filenames (better to use the same type that FileField uses: nvarchar(100)), blob field (image type for example) and size field (bigint). You can’t just create blob column in the same table, where you defined FileField, since there is no way to find required row in the save() method. Also size field is required to obtain better perfomance (see size() method).

So you can use it with different FileFields and even with different “upload_to” variables used. Thus it implements a kind of root filesystem, where you can define dirs using “upload_to” with FileField and store any files in these dirs.

It uses either settings.DB_FILES_URL or constructor param ‘base_url’ (see __init__()) to create urls to files. Base url should be mapped to view that provides access to files. To store files in the same table, where FileField is defined you have to define your own field and provide extra argument (e.g. pk) to save().

Raw sql is used for all operations. In constructor or in DB_FILES of () you should specify a dictionary with db_table, fname_column, blob_column, size_column and ‘base_url’. For example I just put to the the following line:

    'db_table': 'FILES',
    'fname_column':  'FILE_NAME',
    'blob_column': 'BLOB',
    'size_column': 'SIZE',
    'base_url': 'http://localhost/dbfiles/'

And use it with ImageField as following:

player_photo = models.ImageField(upload_to="player_photos", storage=DatabaseStorage() )

DatabaseStorage class uses your file to perform custom connection to your database.

The reason to use custom connection: Connection string looks like:

cnxn = pyodbc.connect('DRIVER={SQL Server};SERVER=localhost;DATABASE=testdb;UID=me;PWD=pass')

It’s based on pyodbc module, so can be used with any database supported by pyodbc. I’ve tested it with MS Sql Express 2005.

Note: It returns special path, which should be mapped to special view, which returns requested file:

def image_view(request, filename):
    import os
    from django.http import HttpResponse
    from django.conf import settings
    from django.utils._os import safe_join
    from filestorage import DatabaseStorage
    from django.core.exceptions import ObjectDoesNotExist

    storage = DatabaseStorage()

        image_file =, 'rb')
        file_content =
        filename = 'no_image.gif'
        path = safe_join(os.path.abspath(settings.MEDIA_ROOT), filename)
        if not os.path.exists(path):
            raise ObjectDoesNotExist
        no_image = open(path, 'rb')
        file_content =

    response = HttpResponse(file_content, mimetype="image/jpeg")
    response['Content-Disposition'] = 'inline; filename=%s'%filename
    return response

Note: If filename exist, blob will be overwritten, to change this remove get_available_name(self, name), so Storage.get_available_name(self, name) will be used to generate new filename.

Project Versions

Previous topic


Next topic


This Page